A Function and Its Integral Function

Integration seen in one picture: the area piling up under a function is the height of its integral function. Move the stopping point and both numbers move together; a taller f delivers more area per step, so F climbs more steeply; and the area between a and b is F(b) - F(a), the subtraction in which the constant C cancels.

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Integration is usually taught as a set of rules for turning one expression into another. The idea underneath is far simpler, and it can be seen in a single picture: the area piling up under a function is the height of its integral function.

Note Two graphs, one number

Take the constant function . Its integral function is , and for now we can set the constant aside and use .

area = 2 2 2 2 f (x) = 1 F (x) = x
Stop at . The region under from the start to that point is a rectangle of width and height , so its area is .

Now read the lower graph at the same place: . The area above and the height below are the same number, and they stay the same number wherever you stop.

Example Moving the stopping point

Same two graphs, three different stopping points.

Stop at : area , and
Stop at : area , and
Stop at : area , and
⟹ area under up to a point value of at that point

Nothing here depends on the numbers being easy. The rule is what defines the integral function in the first place.

Note A rising function forces a steepening integral

The constant case hides something, because every step to the right adds the same slab of area. Take instead, where each step adds more area than the last.

1.5 3.5 1 2 3 4 2 4 f (x) = x F (x) = x²/2
The strip from to has area . The strip from to is the same width but has area .

More area arriving per step means has to climb faster to keep matching it. That is why the lower curve bends upward: its slope at each point is exactly the height of there.

Definition The area between two points

If records the area accumulated up to a point, then the area between and is what has accumulated by , minus what had already accumulated by .

The upper limit is evaluated first and the lower limit is subtracted from it. The constant never survives this subtraction, which is why it does not appear in a definite integral.

Example The area under from 1 to 4

The integral function is .

Subtract:
⟹

The region is a trapezium with parallel sides and and width , so its area is . The geometry and the integral agree, as they must.

Summary
  1. The area under up to a point equals the value of at that point.
  2. Move the stopping point and both numbers move together.
  3. A taller delivers more area per step, so climbs more steeply.
  4. The slope of at any point is the height of there.
  5. For the area between and , evaluate at both and subtract.
  6. The constant cancels in that subtraction, so definite integrals do not carry it.