Combinations

Choosing a group when the order does not matter. How C(n, r) = n! / (r!(n-r)!) works, why dividing by r! cancels the repeated orderings, and how combinations differ from permutations.

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Combinations — Moosa Academy

A combination is a way of choosing a group from a larger set when the order does not matter. Picking Ahmed, Sara, and Mohammed for a team is the same choice however you list them.

Combinations Choosing a group

A combination chooses  r elements from  n with no regard to order, so  \{A, B, C\} and  \{C, B, A\} are the same combination — counted once.

Use combinations whenever you pick a group — a team, a committee, a hand of cards — where it does not matter who was chosen first.

Formula The combinations formula

 C(n, r) = \frac{n!}{r!\,(n-r)!}

 n = the total number of elements,  r = the number chosen.
Dividing by  r! cancels the different orderings of the same group.
So a combination is a permutation with order removed:  C(n, r) = \dfrac{P(n, r)}{r!} .
Example A 5-team league
C(5, 2) = 10 matches

Five teams, each pair playing once. Order does not matter, so count pairs:

 C(5, 2) = \dfrac{5!}{2!\,3!} = \dfrac{120}{12} .
⟹ 10 matches.
Example Three more

A committee of 4 from a class of 12

 C(12, 4) = \dfrac{12!}{4!\,8!} .
⟹ 495 ways.

Choosing 3 salads from 8 kinds

 C(8, 3) = \dfrac{8!}{3!\,5!} .
⟹ 56 choices.

A lineup of 5 players from 15

 C(15, 5) = \dfrac{15!}{5!\,10!} .
⟹ 3,003 different lineups.
Reference Combinations vs permutations
Property Combinations C(n, r) Permutations P(n, r)
Order does not matter matters
Formula n! ÷ (r!(n − r)!) n! ÷ (n − r)!
Result smaller (or equal) larger (or equal)
Example choosing a team of 3 ranking 3 in positions
C(5, 2) vs P(5, 2) 10 20
Summary
  1. A combination chooses a group with no regard to order:  C(n, r) = \dfrac{n!}{r!\,(n-r)!} .
  2. Signal words like "group", "committee", or "team" mean you want combinations.
  3.  C is smaller than  P : we divide by  r! to cancel the orderings of the same group.
  4. A combination is a permutation with the order thrown away —  C(n, r) = P(n, r) \div r! .