How a Condition Changes a Probability

Four cars in a draw show how a condition restricts the sample space - raising one probability from a quarter to a half, and driving another all the way to zero.

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How a Condition Changes a Probability — Moosa Academy

Probability questions reward careful reading. Every extra phrase is doing work: it can raise the probability, lower it, or wipe it out entirely. The reason is always the same — a condition shrinks the set of outcomes still in play.

Concept The set-up: four cars in a draw
Toyota small Toyota large Ford small Ford large
Four cars, one of each kind, all equally likely to be drawn. With nothing else said, each individual car has probability  \tfrac{1}{4} .

The four cars form the sample space — the complete list of things that could happen. Every probability in this lesson is a count of favourable cars divided by the size of that space.

Example No condition at all
 P(\text{Toyota}) = \dfrac{2}{4} = \dfrac{1}{2} — two of the four cars are Toyotas
 P(\text{small Toyota}) = \dfrac{1}{4} — only one car fits

Half the cars are Toyotas, half are Fords, and each specific car is 25%. This is the baseline that the conditions will change.

Example A condition that raises the probability

What is the probability of a small Toyota, given that the car is a Toyota?

Step 1 — the condition rules out both Fords
Step 2 — the sample space shrinks from four cars to two: small Toyota and large Toyota
Step 3 — one of those two is favourable
 P(A \mid B) = \frac{1}{2}
⟹ up from  \tfrac{1}{4} to  \tfrac{1}{2}

Nothing about the car changed — only what is known about it. Knowing it is a Toyota removes half the competition, so the same single car now takes a larger share.

Example A condition that eliminates it

What is the probability of a large Toyota, given that the car is a Ford?

Step 1 — the condition says the car is definitely a Ford
Step 2 — a car cannot be a Ford and a Toyota at the same time
Step 3 — no favourable outcomes remain
 P(A \mid B) = 0
⟹ the condition made it impossible

These two events are mutually exclusive: they cannot both happen. When the condition is one of them, the other drops to zero.

Note The three effects side by side
 P(\text{small Toyota}) = \tfrac{1}{4} — no condition, the baseline
 P(\text{small Toyota} \mid \text{Toyota}) = \tfrac{1}{2} — raised
 P(\text{large Toyota} \mid \text{Ford}) = 0 — eliminated

A condition can also lower a probability without destroying it — that happens when it narrows the sample space but throws away favourable outcomes at the same time. In every case the rule is one and the same: a condition restricts the sample space, and the probability is recalculated inside whatever remains.

Summary
  1. A condition restricts the sample space to the outcomes that satisfy it.
  2. With four equally likely cars, each specific car has probability 1/4.
  3. Given that the car is a Toyota, a small Toyota rises to 1/2 — two cars remain, one is favourable.
  4. Given that the car is a Ford, a large Toyota falls to 0 — the events are mutually exclusive.
  5. Read every phrase in a probability question: each one may change the answer.