قاعدة كرامر لحل نظام من معادلتين
طريقة كريمر لحل نظام المعادلات
الرياضيات — الوحدة الأولى
— مناسبة للبرمجة لكونها ذات خطوات ثابتة ومتسلسلة.
— الحل = قسمة المحددات المساعدة على محددة المعاملات.
| الخطوة | الإجراء | الرمز |
|---|---|---|
| ١ | احسب محددة المعاملات | |
| ٢ | استبدل عمود | |
| ٣ | استبدل عمود | |
| ٤ | ||
| ٥ | ||
| ٦ | تحقق بالتعويض في الأصل | ✓ |
— المصفوفة المساعدة: استبدل عمود المتغير المطلوب بعمود الثوابت فقط.
— القانون: x = Dx/D، y = Dy/D — قسمة مباشرة.
— التحقق: عوّض في المعادلتين الأصليتين للتأكد من صحة الحل.
تمارين طريقة كريمر
الرياضيات — الوحدة الأولى
x = 4
y = 3
x = 5
y = -6
| المسألة | الحل | |||
|---|---|---|---|---|
| أ | −34 | −136 | −102 | |
| ب | 101 | 505 | −606 |
اختبار: طريقة كريمر لحل نظام المعادلات الخطية
1 / 10في هذا الدرس سنتعلم **طريقة كرامر** لحل نظام المعادلات الخطية.
ما هي طريقة كرامر؟
تعتمد طريقة كرامر على حساب **محددات المصفوفات** المستخرجة من نظام المعادلات.
ومن أهم مميزاتها أنها طريقة منتظمة، لذلك يمكن تحويلها بسهولة إلى خوارزميات تنفذها أجهزة الحاسب.
مثال
لدينا نظام المعادلتين:
<div class="math-display" style="text-align:center;margin:10px 0;direction:ltr;overflow-x:auto;max-width:100%;"><svg aria-label="5x-6y=15" data-tex="5x-6y=15" style="display:block;margin:0 auto;vertical-align: -0.464ex;" xmlns="http://www.w3.org/2000/svg" width="12.71ex" height="1.971ex" role="img" focusable="false" viewBox="0 -666 5618 871" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="mn"><use data-c="35" xlink:href="#MJXG-TEX-N-35"></use></g><g data-mml-node="mi" transform="translate(500,0)"><use data-c="1D465" xlink:href="#MJXG-TEX-I-1D465"></use></g><g data-mml-node="mo" transform="translate(1294.2,0)"><use data-c="2212" xlink:href="#MJXG-TEX-N-2212"></use></g><g data-mml-node="mn" transform="translate(2294.4,0)"><use data-c="36" xlink:href="#MJXG-TEX-N-36"></use></g><g data-mml-node="mi" transform="translate(2794.4,0)"><use data-c="1D466" xlink:href="#MJXG-TEX-I-1D466"></use></g><g data-mml-node="mo" transform="translate(3562.2,0)"><use data-c="3D" xlink:href="#MJXG-TEX-N-3D"></use></g><g data-mml-node="mn" transform="translate(4618,0)"><use data-c="31" xlink:href="#MJXG-TEX-N-31"></use><use data-c="35" xlink:href="#MJXG-TEX-N-35" transform="translate(500,0)"></use></g></g></g></svg></div>
<div class="math-display" style="text-align:center;margin:10px 0;direction:ltr;overflow-x:auto;max-width:100%;"><svg aria-label="3x+4y=-29" data-tex="3x+4y=-29" style="display:block;margin:0 auto;vertical-align: -0.464ex;" xmlns="http://www.w3.org/2000/svg" width="14.471ex" height="1.995ex" role="img" focusable="false" viewBox="0 -677 6396 882" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="mn"><use data-c="33" xlink:href="#MJXG-TEX-N-33"></use></g><g data-mml-node="mi" transform="translate(500,0)"><use data-c="1D465" xlink:href="#MJXG-TEX-I-1D465"></use></g><g data-mml-node="mo" transform="translate(1294.2,0)"><use data-c="2B" xlink:href="#MJXG-TEX-N-2B"></use></g><g data-mml-node="mn" transform="translate(2294.4,0)"><use data-c="34" xlink:href="#MJXG-TEX-N-34"></use></g><g data-mml-node="mi" transform="translate(2794.4,0)"><use data-c="1D466" xlink:href="#MJXG-TEX-I-1D466"></use></g><g data-mml-node="mo" transform="translate(3562.2,0)"><use data-c="3D" xlink:href="#MJXG-TEX-N-3D"></use></g><g data-mml-node="mo" transform="translate(4618,0)"><use data-c="2212" xlink:href="#MJXG-TEX-N-2212"></use></g><g data-mml-node="mn" transform="translate(5396,0)"><use data-c="32" xlink:href="#MJXG-TEX-N-32"></use><use data-c="39" xlink:href="#MJXG-TEX-N-39" transform="translate(500,0)"></use></g></g></g></svg></div>
الخطوة الأولى: تكوين مصفوفة المعاملات
نأخذ معاملات المتغيرين فقط، فنحصل على مصفوفة المعاملات:
<div class="math-display" style="text-align:center;margin:10px 0;direction:ltr;overflow-x:auto;max-width:100%;"><svg aria-label="\begin{bmatrix} 5 & -6\\ 3 & 4 \end{bmatrix}" data-tex="\begin{bmatrix} 5 & -6\\ 3 & 4 \end{bmatrix}" style="display:block;margin:0 auto;vertical-align: -2.149ex;" xmlns="http://www.w3.org/2000/svg" width="8.674ex" height="5.43ex" role="img" focusable="false" viewBox="0 -1450 3834 2400" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="mrow"><g data-mml-node="mo" transform="translate(0 -0.5)"><use data-c="5B" xlink:href="#MJXG-TEX-S3-5B"></use></g><g data-mml-node="mtable" transform="translate(528,0)"><g data-mml-node="mtr" transform="translate(0,700)"><g data-mml-node="mtd"><g data-mml-node="mn"><use data-c="35" xlink:href="#MJXG-TEX-N-35"></use></g></g><g data-mml-node="mtd" transform="translate(1500,0)"><g data-mml-node="mo"><use data-c="2212" xlink:href="#MJXG-TEX-N-2212"></use></g><g data-mml-node="mn" transform="translate(778,0)"><use data-c="36" xlink:href="#MJXG-TEX-N-36"></use></g></g></g><g data-mml-node="mtr" transform="translate(0,-700)"><g data-mml-node="mtd"><g data-mml-node="mn"><use data-c="33" xlink:href="#MJXG-TEX-N-33"></use></g></g><g data-mml-node="mtd" transform="translate(1889,0)"><g data-mml-node="mn"><use data-c="34" xlink:href="#MJXG-TEX-N-34"></use></g></g></g></g><g data-mml-node="mo" transform="translate(3306,0) translate(0 -0.5)"><use data-c="5D" xlink:href="#MJXG-TEX-S3-5D"></use></g></g></g></g></svg></div>
ثم نحسب محددها بالطريقة التي تعلمناها سابقًا:
**حاصل ضرب القطر الرئيسي ناقص حاصل ضرب القطر الثانوي.**
فتكون قيمة محدد المعاملات:
<div class="math-display" style="text-align:center;margin:10px 0;direction:ltr;overflow-x:auto;max-width:100%;"><svg aria-label="D=38" data-tex="D=38" style="display:block;margin:0 auto;vertical-align: -0.186ex;" xmlns="http://www.w3.org/2000/svg" width="7.153ex" height="1.731ex" role="img" focusable="false" viewBox="0 -683 3161.6 765" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="mi"><use data-c="1D437" xlink:href="#MJXG-TEX-I-1D437"></use></g><g data-mml-node="mo" transform="translate(1105.8,0)"><use data-c="3D" xlink:href="#MJXG-TEX-N-3D"></use></g><g data-mml-node="mn" transform="translate(2161.6,0)"><use data-c="33" xlink:href="#MJXG-TEX-N-33"></use><use data-c="38" xlink:href="#MJXG-TEX-N-38" transform="translate(500,0)"></use></g></g></g></svg></div>
الخطوة الثانية: إيجاد قيمة <span class="math-inline" dir="ltr" style="display:inline-block;direction:ltr;unicode-bidi:isolate;vertical-align:baseline;white-space:nowrap;margin:0 2px;"><svg aria-label="x" data-tex="x" style="display:inline-block;vertical-align: -0.025ex;" xmlns="http://www.w3.org/2000/svg" width="1.294ex" height="1.025ex" role="img" focusable="false" viewBox="0 -442 572 453" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="mi"><use data-c="1D465" xlink:href="#MJXG-TEX-I-1D465"></use></g></g></g></svg></span>
لحساب محدد <span class="math-inline" dir="ltr" style="display:inline-block;direction:ltr;unicode-bidi:isolate;vertical-align:baseline;white-space:nowrap;margin:0 2px;"><svg aria-label="D_x" data-tex="D_x" style="display:inline-block;vertical-align: -0.357ex;" xmlns="http://www.w3.org/2000/svg" width="2.976ex" height="1.902ex" role="img" focusable="false" viewBox="0 -683 1315.5 840.8" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="msub"><g data-mml-node="mi"><use data-c="1D437" xlink:href="#MJXG-TEX-I-1D437"></use></g><g data-mml-node="mi" transform="translate(861,-150) scale(0.707)"><use data-c="1D465" xlink:href="#MJXG-TEX-I-1D465"></use></g></g></g></g></svg></span>:
نستبدل **عمود <span class="math-inline" dir="ltr" style="display:inline-block;direction:ltr;unicode-bidi:isolate;vertical-align:baseline;white-space:nowrap;margin:0 2px;"><svg aria-label="x" data-tex="x" style="display:inline-block;vertical-align: -0.025ex;" xmlns="http://www.w3.org/2000/svg" width="1.294ex" height="1.025ex" role="img" focusable="false" viewBox="0 -442 572 453" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="mi"><use data-c="1D465" xlink:href="#MJXG-TEX-I-1D465"></use></g></g></g></svg></span>** بالحدود الثابتة الموجودة بعد علامة المساواة، بينما يبقى عمود <span class="math-inline" dir="ltr" style="display:inline-block;direction:ltr;unicode-bidi:isolate;vertical-align:baseline;white-space:nowrap;margin:0 2px;"><svg aria-label="y" data-tex="y" style="display:inline-block;vertical-align: -0.464ex;" xmlns="http://www.w3.org/2000/svg" width="1.109ex" height="1.464ex" role="img" focusable="false" viewBox="0 -442 490 647" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="mi"><use data-c="1D466" xlink:href="#MJXG-TEX-I-1D466"></use></g></g></g></svg></span> كما هو.
بعد حساب المحدد نجد:
<div class="math-display" style="text-align:center;margin:10px 0;direction:ltr;overflow-x:auto;max-width:100%;"><svg aria-label="D_x=-114" data-tex="D_x=-114" style="display:block;margin:0 auto;vertical-align: -0.357ex;" xmlns="http://www.w3.org/2000/svg" width="11.147ex" height="1.902ex" role="img" focusable="false" viewBox="0 -683 4927 840.8" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="msub"><g data-mml-node="mi"><use data-c="1D437" xlink:href="#MJXG-TEX-I-1D437"></use></g><g data-mml-node="mi" transform="translate(861,-150) scale(0.707)"><use data-c="1D465" xlink:href="#MJXG-TEX-I-1D465"></use></g></g><g data-mml-node="mo" transform="translate(1593.2,0)"><use data-c="3D" xlink:href="#MJXG-TEX-N-3D"></use></g><g data-mml-node="mo" transform="translate(2649,0)"><use data-c="2212" xlink:href="#MJXG-TEX-N-2212"></use></g><g data-mml-node="mn" transform="translate(3427,0)"><use data-c="31" xlink:href="#MJXG-TEX-N-31"></use><use data-c="31" xlink:href="#MJXG-TEX-N-31" transform="translate(500,0)"></use><use data-c="34" xlink:href="#MJXG-TEX-N-34" transform="translate(1000,0)"></use></g></g></g></svg></div>
ثم نطبق قانون كرامر:
<div class="math-display" style="text-align:center;margin:10px 0;direction:ltr;overflow-x:auto;max-width:100%;"><svg aria-label="x=\frac{D_x}{D} =\frac{-114}{38} =-3" data-tex="x=\frac{D_x}{D} =\frac{-114}{38} =-3" style="display:block;margin:0 auto;vertical-align: -1.602ex;" xmlns="http://www.w3.org/2000/svg" width="23.358ex" height="4.676ex" role="img" focusable="false" viewBox="0 -1359 10324.1 2067" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="mi"><use data-c="1D465" xlink:href="#MJXG-TEX-I-1D465"></use></g><g data-mml-node="mo" transform="translate(849.8,0)"><use data-c="3D" xlink:href="#MJXG-TEX-N-3D"></use></g><g data-mml-node="mfrac" transform="translate(1905.6,0)"><g data-mml-node="msub" transform="translate(220,676)"><g data-mml-node="mi"><use data-c="1D437" xlink:href="#MJXG-TEX-I-1D437"></use></g><g data-mml-node="mi" transform="translate(861,-150) scale(0.707)"><use data-c="1D465" xlink:href="#MJXG-TEX-I-1D465"></use></g></g><g data-mml-node="mi" transform="translate(463.7,-686)"><use data-c="1D437" xlink:href="#MJXG-TEX-I-1D437"></use></g><rect width="1515.5" height="60" x="120" y="220"></rect></g><g data-mml-node="mo" transform="translate(3938.8,0)"><use data-c="3D" xlink:href="#MJXG-TEX-N-3D"></use></g><g data-mml-node="mfrac" transform="translate(4994.6,0)"><g data-mml-node="mrow" transform="translate(220,676)"><g data-mml-node="mo"><use data-c="2212" xlink:href="#MJXG-TEX-N-2212"></use></g><g data-mml-node="mn" transform="translate(778,0)"><use data-c="31" xlink:href="#MJXG-TEX-N-31"></use><use data-c="31" xlink:href="#MJXG-TEX-N-31" transform="translate(500,0)"></use><use data-c="34" xlink:href="#MJXG-TEX-N-34" transform="translate(1000,0)"></use></g></g><g data-mml-node="mn" transform="translate(859,-686)"><use data-c="33" xlink:href="#MJXG-TEX-N-33"></use><use data-c="38" xlink:href="#MJXG-TEX-N-38" transform="translate(500,0)"></use></g><rect width="2478" height="60" x="120" y="220"></rect></g><g data-mml-node="mo" transform="translate(7990.4,0)"><use data-c="3D" xlink:href="#MJXG-TEX-N-3D"></use></g><g data-mml-node="mo" transform="translate(9046.1,0)"><use data-c="2212" xlink:href="#MJXG-TEX-N-2212"></use></g><g data-mml-node="mn" transform="translate(9824.1,0)"><use data-c="33" xlink:href="#MJXG-TEX-N-33"></use></g></g></g></svg></div>
الخطوة الثالثة: إيجاد قيمة <span class="math-inline" dir="ltr" style="display:inline-block;direction:ltr;unicode-bidi:isolate;vertical-align:baseline;white-space:nowrap;margin:0 2px;"><svg aria-label="y" data-tex="y" style="display:inline-block;vertical-align: -0.464ex;" xmlns="http://www.w3.org/2000/svg" width="1.109ex" height="1.464ex" role="img" focusable="false" viewBox="0 -442 490 647" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="mi"><use data-c="1D466" xlink:href="#MJXG-TEX-I-1D466"></use></g></g></g></svg></span>
لحساب محدد <span class="math-inline" dir="ltr" style="display:inline-block;direction:ltr;unicode-bidi:isolate;vertical-align:baseline;white-space:nowrap;margin:0 2px;"><svg aria-label="D_y" data-tex="D_y" style="display:inline-block;vertical-align: -0.667ex;" xmlns="http://www.w3.org/2000/svg" width="2.845ex" height="2.213ex" role="img" focusable="false" viewBox="0 -683 1257.5 978" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="msub"><g data-mml-node="mi"><use data-c="1D437" xlink:href="#MJXG-TEX-I-1D437"></use></g><g data-mml-node="mi" transform="translate(861,-150) scale(0.707)"><use data-c="1D466" xlink:href="#MJXG-TEX-I-1D466"></use></g></g></g></g></svg></span>:
نستبدل **عمود <span class="math-inline" dir="ltr" style="display:inline-block;direction:ltr;unicode-bidi:isolate;vertical-align:baseline;white-space:nowrap;margin:0 2px;"><svg aria-label="y" data-tex="y" style="display:inline-block;vertical-align: -0.464ex;" xmlns="http://www.w3.org/2000/svg" width="1.109ex" height="1.464ex" role="img" focusable="false" viewBox="0 -442 490 647" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="mi"><use data-c="1D466" xlink:href="#MJXG-TEX-I-1D466"></use></g></g></g></svg></span>** بالحدود الثابتة، بينما يبقى عمود <span class="math-inline" dir="ltr" style="display:inline-block;direction:ltr;unicode-bidi:isolate;vertical-align:baseline;white-space:nowrap;margin:0 2px;"><svg aria-label="x" data-tex="x" style="display:inline-block;vertical-align: -0.025ex;" xmlns="http://www.w3.org/2000/svg" width="1.294ex" height="1.025ex" role="img" focusable="false" viewBox="0 -442 572 453" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="mi"><use data-c="1D465" xlink:href="#MJXG-TEX-I-1D465"></use></g></g></g></svg></span> كما هو.
بعد حساب المحدد نجد:
<div class="math-display" style="text-align:center;margin:10px 0;direction:ltr;overflow-x:auto;max-width:100%;"><svg aria-label="D_y=-190" data-tex="D_y=-190" style="display:block;margin:0 auto;vertical-align: -0.667ex;" xmlns="http://www.w3.org/2000/svg" width="11.016ex" height="2.213ex" role="img" focusable="false" viewBox="0 -683 4869 978" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="msub"><g data-mml-node="mi"><use data-c="1D437" xlink:href="#MJXG-TEX-I-1D437"></use></g><g data-mml-node="mi" transform="translate(861,-150) scale(0.707)"><use data-c="1D466" xlink:href="#MJXG-TEX-I-1D466"></use></g></g><g data-mml-node="mo" transform="translate(1535.3,0)"><use data-c="3D" xlink:href="#MJXG-TEX-N-3D"></use></g><g data-mml-node="mo" transform="translate(2591,0)"><use data-c="2212" xlink:href="#MJXG-TEX-N-2212"></use></g><g data-mml-node="mn" transform="translate(3369,0)"><use data-c="31" xlink:href="#MJXG-TEX-N-31"></use><use data-c="39" xlink:href="#MJXG-TEX-N-39" transform="translate(500,0)"></use><use data-c="30" xlink:href="#MJXG-TEX-N-30" transform="translate(1000,0)"></use></g></g></g></svg></div>
ثم نطبق القانون:
<div class="math-display" style="text-align:center;margin:10px 0;direction:ltr;overflow-x:auto;max-width:100%;"><svg aria-label="y=\frac{D_y}{D} =\frac{-190}{38} =-5" data-tex="y=\frac{D_y}{D} =\frac{-190}{38} =-5" style="display:block;margin:0 auto;vertical-align: -1.602ex;" xmlns="http://www.w3.org/2000/svg" width="23.041ex" height="4.855ex" role="img" focusable="false" viewBox="0 -1438 10184.1 2146" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="mi"><use data-c="1D466" xlink:href="#MJXG-TEX-I-1D466"></use></g><g data-mml-node="mo" transform="translate(767.8,0)"><use data-c="3D" xlink:href="#MJXG-TEX-N-3D"></use></g><g data-mml-node="mfrac" transform="translate(1823.6,0)"><g data-mml-node="msub" transform="translate(220,755)"><g data-mml-node="mi"><use data-c="1D437" xlink:href="#MJXG-TEX-I-1D437"></use></g><g data-mml-node="mi" transform="translate(861,-150) scale(0.707)"><use data-c="1D466" xlink:href="#MJXG-TEX-I-1D466"></use></g></g><g data-mml-node="mi" transform="translate(434.7,-686)"><use data-c="1D437" xlink:href="#MJXG-TEX-I-1D437"></use></g><rect width="1457.5" height="60" x="120" y="220"></rect></g><g data-mml-node="mo" transform="translate(3798.8,0)"><use data-c="3D" xlink:href="#MJXG-TEX-N-3D"></use></g><g data-mml-node="mfrac" transform="translate(4854.6,0)"><g data-mml-node="mrow" transform="translate(220,676)"><g data-mml-node="mo"><use data-c="2212" xlink:href="#MJXG-TEX-N-2212"></use></g><g data-mml-node="mn" transform="translate(778,0)"><use data-c="31" xlink:href="#MJXG-TEX-N-31"></use><use data-c="39" xlink:href="#MJXG-TEX-N-39" transform="translate(500,0)"></use><use data-c="30" xlink:href="#MJXG-TEX-N-30" transform="translate(1000,0)"></use></g></g><g data-mml-node="mn" transform="translate(859,-686)"><use data-c="33" xlink:href="#MJXG-TEX-N-33"></use><use data-c="38" xlink:href="#MJXG-TEX-N-38" transform="translate(500,0)"></use></g><rect width="2478" height="60" x="120" y="220"></rect></g><g data-mml-node="mo" transform="translate(7850.4,0)"><use data-c="3D" xlink:href="#MJXG-TEX-N-3D"></use></g><g data-mml-node="mo" transform="translate(8906.1,0)"><use data-c="2212" xlink:href="#MJXG-TEX-N-2212"></use></g><g data-mml-node="mn" transform="translate(9684.1,0)"><use data-c="35" xlink:href="#MJXG-TEX-N-35"></use></g></g></g></svg></div>
الخلاصة
لحل نظام معادلتين بطريقة كرامر:
1. نكوّن مصفوفة المعاملات ونحسب محددها <span class="math-inline" dir="ltr" style="display:inline-block;direction:ltr;unicode-bidi:isolate;vertical-align:baseline;white-space:nowrap;margin:0 2px;"><svg aria-label="D" data-tex="D" style="display:inline-block;vertical-align: 0;" xmlns="http://www.w3.org/2000/svg" width="1.873ex" height="1.545ex" role="img" focusable="false" viewBox="0 -683 828 683" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="mi"><use data-c="1D437" xlink:href="#MJXG-TEX-I-1D437"></use></g></g></g></svg></span>. 2. نحسب محدد <span class="math-inline" dir="ltr" style="display:inline-block;direction:ltr;unicode-bidi:isolate;vertical-align:baseline;white-space:nowrap;margin:0 2px;"><svg aria-label="D_x" data-tex="D_x" style="display:inline-block;vertical-align: -0.357ex;" xmlns="http://www.w3.org/2000/svg" width="2.976ex" height="1.902ex" role="img" focusable="false" viewBox="0 -683 1315.5 840.8" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="msub"><g data-mml-node="mi"><use data-c="1D437" xlink:href="#MJXG-TEX-I-1D437"></use></g><g data-mml-node="mi" transform="translate(861,-150) scale(0.707)"><use data-c="1D465" xlink:href="#MJXG-TEX-I-1D465"></use></g></g></g></g></svg></span> باستبدال عمود <span class="math-inline" dir="ltr" style="display:inline-block;direction:ltr;unicode-bidi:isolate;vertical-align:baseline;white-space:nowrap;margin:0 2px;"><svg aria-label="x" data-tex="x" style="display:inline-block;vertical-align: -0.025ex;" xmlns="http://www.w3.org/2000/svg" width="1.294ex" height="1.025ex" role="img" focusable="false" viewBox="0 -442 572 453" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="mi"><use data-c="1D465" xlink:href="#MJXG-TEX-I-1D465"></use></g></g></g></svg></span> بالحدود الثابتة. 3. نحسب محدد <span class="math-inline" dir="ltr" style="display:inline-block;direction:ltr;unicode-bidi:isolate;vertical-align:baseline;white-space:nowrap;margin:0 2px;"><svg aria-label="D_y" data-tex="D_y" style="display:inline-block;vertical-align: -0.667ex;" xmlns="http://www.w3.org/2000/svg" width="2.845ex" height="2.213ex" role="img" focusable="false" viewBox="0 -683 1257.5 978" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="msub"><g data-mml-node="mi"><use data-c="1D437" xlink:href="#MJXG-TEX-I-1D437"></use></g><g data-mml-node="mi" transform="translate(861,-150) scale(0.707)"><use data-c="1D466" xlink:href="#MJXG-TEX-I-1D466"></use></g></g></g></g></svg></span> باستبدال عمود <span class="math-inline" dir="ltr" style="display:inline-block;direction:ltr;unicode-bidi:isolate;vertical-align:baseline;white-space:nowrap;margin:0 2px;"><svg aria-label="y" data-tex="y" style="display:inline-block;vertical-align: -0.464ex;" xmlns="http://www.w3.org/2000/svg" width="1.109ex" height="1.464ex" role="img" focusable="false" viewBox="0 -442 490 647" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="mi"><use data-c="1D466" xlink:href="#MJXG-TEX-I-1D466"></use></g></g></g></svg></span> بالحدود الثابتة. 4. نحسب الحل باستخدام:
<div class="math-display" style="text-align:center;margin:10px 0;direction:ltr;overflow-x:auto;max-width:100%;"><svg aria-label="x=\frac{D_x}{D}" data-tex="x=\frac{D_x}{D}" style="display:block;margin:0 auto;vertical-align: -1.552ex;" xmlns="http://www.w3.org/2000/svg" width="8.283ex" height="4.627ex" role="img" focusable="false" viewBox="0 -1359 3661 2045" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="mi"><use data-c="1D465" xlink:href="#MJXG-TEX-I-1D465"></use></g><g data-mml-node="mo" transform="translate(849.8,0)"><use data-c="3D" xlink:href="#MJXG-TEX-N-3D"></use></g><g data-mml-node="mfrac" transform="translate(1905.6,0)"><g data-mml-node="msub" transform="translate(220,676)"><g data-mml-node="mi"><use data-c="1D437" xlink:href="#MJXG-TEX-I-1D437"></use></g><g data-mml-node="mi" transform="translate(861,-150) scale(0.707)"><use data-c="1D465" xlink:href="#MJXG-TEX-I-1D465"></use></g></g><g data-mml-node="mi" transform="translate(463.7,-686)"><use data-c="1D437" xlink:href="#MJXG-TEX-I-1D437"></use></g><rect width="1515.5" height="60" x="120" y="220"></rect></g></g></g></svg></div>
<div class="math-display" style="text-align:center;margin:10px 0;direction:ltr;overflow-x:auto;max-width:100%;"><svg aria-label="y=\frac{D_y}{D}" data-tex="y=\frac{D_y}{D}" style="display:block;margin:0 auto;vertical-align: -1.552ex;" xmlns="http://www.w3.org/2000/svg" width="7.966ex" height="4.805ex" role="img" focusable="false" viewBox="0 -1438 3521 2124" xmlns:xlink="http://www.w3.org/1999/xlink"><g stroke="currentColor" fill="currentColor" stroke-width="0" transform="scale(1,-1)"><g data-mml-node="math"><g data-mml-node="mi"><use data-c="1D466" xlink:href="#MJXG-TEX-I-1D466"></use></g><g data-mml-node="mo" transform="translate(767.8,0)"><use data-c="3D" xlink:href="#MJXG-TEX-N-3D"></use></g><g data-mml-node="mfrac" transform="translate(1823.6,0)"><g data-mml-node="msub" transform="translate(220,755)"><g data-mml-node="mi"><use data-c="1D437" xlink:href="#MJXG-TEX-I-1D437"></use></g><g data-mml-node="mi" transform="translate(861,-150) scale(0.707)"><use data-c="1D466" xlink:href="#MJXG-TEX-I-1D466"></use></g></g><g data-mml-node="mi" transform="translate(434.7,-686)"><use data-c="1D437" xlink:href="#MJXG-TEX-I-1D437"></use></g><rect width="1457.5" height="60" x="120" y="220"></rect></g></g></g></svg></div>
وبذلك نحصل على قيم المتغيرين بطريقة منظمة وسهلة.
عن هذا الدرس
في هذا الدرس سنتعلم طريقة كرامر لحل نظام المعادلات الخطية. ما هي طريقة كرامر؟ تعتمد طريقة كرامر على حساب محددات المصفوفات المستخرجة من نظام المعادلات. ومن… هذا الدرس ضمن الفصل الأول لمنهج الثانوية ثاني ثانوي في أكاديمية موسى.
